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# Circular Motion Assignment Help

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Classical Physics - Circular Motion

**Circular Motion**

Circular motion may be divided into two types **(a) **motion in a horizontal circle** (b) **motion in a vertical circle. The basic differed being that in case of vertical circle acceleration due to gravity plays a role at every point and changes the speed at every point. We will deal with them separately.

**Motion in a horizontal circle: - **here acceleration acts continuously even when speed is uniform, therefore, impel equation of motion as used in translation motion cannot be applied. We define new variables and equations to describe motion.

Angular displacement **(θ)** change in angular position (initial to final)is called angular displacement.

Angular velocity (ω) time rate of change of angular displacement is called angular velocity.

**Thus ω = dθ / dt**

Angular acceleration** (a) **time rate of change of angular velocity is called angular acceleration.

**α =dω / dt = d**^{2}θ / dt^{2}

if the angular acceleration is constant then

**ω = ωo + αt**

ωav = 2π / T

Where **T** is time period to completer circle.

**θ = ωot + 1 / 2 αt2**

**ω**^{2} – ω^{2}o + 2 αθ

Relation between** v **and **ax a **and **α**

**V = rω **where **r **is radius of the circular path.

**αt = rα **where at is tangential acceleration as explained in

Centripetal or radial acceleration **ar = v**^{2} / r = rω^{2}

Net acceleration **a**_{net} **= √a**^{2}t + a^{2}r tan β = ar / at

Centripetal force** F = mv**^{2} / r = mrω^{2}. It is a pseudo of orca. It acts towards the centre.

Centrifugal force the initial reaction required to take into account the acceleration of frame of reference is called centrifugal force. It is equal to **– mrω**^{2}

Motion in a vertical circle when a body moves in a vertical circle then at the highest point

**mv**^{2} / r ≥ mg v_{min} = √rg at highest point

v_{min} at any point **P** can be determined using the fact that the body has come down by a vertical distance

**AX = AO + OX = r + r cos θ (form)**

Thus **v**^{2}_{min} p = **v**^{2}_{min} **A + 2 gh**

**= rg + 2g (r + r cosθ)**

= 3 rg + 2rg cps θ

**v**_{min}p = √3rg + 2rg cos θ

**v**_{min} at lowed point or bottom is obtained by using **θ = 0**

That is, **v**_{min} bottom **= √5rg**

Tension, if the string is used or normal reaction at any point **P** is obtained as

**T or N = mv**^{2} / r + mg cos θ

Where **v** is velocity at that point.

ExpertsMind.com - Physics Assignment Help, Circular Motion Assignment Help, Circular Motion Homework Help, Circular Motion Assignment Tutors, Circular Motion Solutions, Circular Motion Answers, Classical Physics Assignment Tutors

**Circular Motion**

**(a)**motion in a horizontal circle

**(b)**motion in a vertical circle. The basic differed being that in case of vertical circle acceleration due to gravity plays a role at every point and changes the speed at every point. We will deal with them separately.

**Motion in a horizontal circle: -**here acceleration acts continuously even when speed is uniform, therefore, impel equation of motion as used in translation motion cannot be applied. We define new variables and equations to describe motion.

Angular displacement

**(θ)**change in angular position (initial to final)is called angular displacement.

Angular velocity (ω) time rate of change of angular displacement is called angular velocity.

**Thus ω = dθ / dt**

Angular acceleration

**(a)**time rate of change of angular velocity is called angular acceleration.

**α =dω / dt = d**

^{2}θ / dt^{2}

if the angular acceleration is constant then

**ω = ωo + αt**

ωav = 2π / T

ωav = 2π / T

Where

**T**is time period to completer circle.

**θ = ωot + 1 / 2 αt2**

**ω**

^{2}– ω^{2}o + 2 αθRelation between

**v**and

**ax a**and

**α**

**V = rω**where

**r**is radius of the circular path.

**αt = rα**where at is tangential acceleration as explained in

Centripetal or radial acceleration

**ar = v**

^{2}/ r = rω^{2}

Net acceleration

**a**

_{net}

**= √a**

^{2}t + a^{2}r tan β = ar / atCentripetal force

**F = mv**It is a pseudo of orca. It acts towards the centre.

^{2}/ r = mrω^{2}.Centrifugal force the initial reaction required to take into account the acceleration of frame of reference is called centrifugal force. It is equal to

**– mrω**

^{2}

Motion in a vertical circle when a body moves in a vertical circle then at the highest point

**mv**at highest point

^{2}/ r ≥ mg v_{min}= √rg**at any point**

v

v

_{min}**P**can be determined using the fact that the body has come down by a vertical distance

**AX = AO + OX = r + r cos θ (form)**

Thus

**v**p =

^{2}_{min}**v**

^{2}_{min}**A + 2 gh**

**= rg + 2g (r + r cosθ)**

= 3 rg + 2rg cps θ

= 3 rg + 2rg cps θ

**v**p = √3rg + 2rg cos θ_{min}**v**at lowed point or bottom is obtained by using

_{min}**θ = 0**

That is,

**v**bottom

_{min}**= √5rg**

Tension, if the string is used or normal reaction at any point

**P**is obtained as

**T or N = mv**

^{2}/ r + mg cos θWhere

**v**is velocity at that point.

ExpertsMind.com - Physics Assignment Help, Circular Motion Assignment Help, Circular Motion Homework Help, Circular Motion Assignment Tutors, Circular Motion Solutions, Circular Motion Answers, Classical Physics Assignment Tutors