If the angle is big there must be a lot of tension thus as

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Reference no: EM13604441

In the bird-on-a-wire group work example, how do you expect the angle and tension to be related? Remember that this is static equilibrium, so the acceleration is zero-no angry bird slingshot here! Answer 1-As long as we keep the bird's weight constant and everything is in static equilibrium, the tension and angle are completely independent. 2-If you increase the tension (relative to the bird's weight mg), you expect the wire to sag less, so the angle gets smaller. 3-Birds can never be in static equilibrium. 4-If the angle is big, there must be a lot of tension. Thus, as you increase the tension relative to the bird's weight, the wire must sag more and the angle gets larger. which one is the right answer?

Reference no: EM13604441

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