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A digital computer has a memory unit with 32 bits per word. The instruction set consists of 128 different operations. All instructions have an operations code part (opcode) and an address part (allowing for only one address). Each instruction is stored in one word of memory.
a. How many bits are needed for the opcode?
b. How many Bits are left for the address part of the instruction?
c. What is the maximum allowable size for memory?
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For a message, he computes the hash value H = (VChar 1 x VChar 2 x VChar 3 ...x VChar N) mod(26).
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