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Acetic acid has a pKa of 4.74. A sodium acetate/ acetic acid buffer (NaCH3CO2/CH3CO2H) with a pH of 4.74 can be made by:
a. Combining 0.10 mole of CH3CO2H with 0.10 mole of NaCH3CO2 in water
b. Combining 0.20 mole of CH3CO2H with 0.20 of NaOH in water
c. Combining 0.20 mole of CH3CO2H with 0.10 mole of NaOH in water
The answers are both A and C, but how? Using the equation pH=pKa+log([base]/[acid]), it seems like it would be A and B.
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A 144-mL portion of that solution is diluted by adding 169 mL of water. What is the final concentration? Assume the volumes are additive.
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