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Hardy-Weinberg has 5 major assumptions; however none of these assumptions are ever met by a natural population. Why then, can we use Hardy-Weinberg to test if a population is at equilibrium?
a)Hardy-Weinberg is not appropriate to use for many genetic data sets because none of the assumptions are met.
b)Hardy - Weinberg simply provides us with a null model to test hypothesis against
c)We only use Hardy-Weinberg in populations that we suspect are at equilibriumd)We can use Hardy-Weinberg if only one of the assumptions is violated
e)We can use Hardy-Weinberg because we accompany it with a ?2 test of significance.
The following individuals are present in a population:MM = 1787MN = 3037NN = 1305Total = 6129
Calculate the expected value of MN and enter the answer with no decimals. When calculating the allele frequency of M and N please use two decimals.
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Does this represent a significant section from the Hardy-Weinberg ratios? Further studies show that the absence of the A/A genotype is due to the lethal effect of the A allele when homozygous.
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