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Question- A solution is made by mixing 500.0 mL of 4.0 M NH3 and 500.0 mL of 0.40 M AgNO3. Ag+ reacts with NH3 to form AgNH3+ and Ag(NH3)2+ according to the equilibrium reactions:
Ag+ + NH3 ? AgNH3+ K¬1 = 2.1 x 103
AgNH3+ + NH3 ? Ag(NH3)2+ K¬2 = 8.2 x 103
Assuming no change in volume on mixing calculate the concentrations of all species in solution: [Ag+], [NO3-], [NH3], [AgNH3+] and [Ag(NH3)2+].
Please explain above problem in step by step manner so I can easily understand it
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