Calculate magnitude of electric field between two plates

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A charged particle is projected in a uniform electric field between two plates with initial velocity 5x10^3m/s at angle 40 degrees to the x-axis. Its charge is q= -1.0x10^-11 C and mass is m=3.0x10^-14 kg. The two parallel plates are separated by d=2.0 cm. The electric potential difference between the two plates is 3,600 volts. The length of the plates is 10.0cm.

a) Calculate the magnitude of the electric field, which is uniform, between two plates, E (vector).

b) and the force acting on the charged ink drop by the field , F (vector), its acceleration in the y-direction, a sub y

c) the time it takes the drop to move out of the of the plates, t, (plates are 10 cm long and 2 cm apart)

d) the y-component of its velocity when the drop leaves the plates, v sub y

e) its velocity and the angle between the velocity of the particle and the x-axis when it leaves the plates.

Reference no: EM13337972

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