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Analysis of Single-phase fully-controlled bridge rectifier feeding an R-L load

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  • "Power ElectronicsSimulation Assignment Analysis of Single-phase fully-controlled bridge rectifier feeding an R-L loadSingle-phase fully-controlled bridge rectifier feeding an R-L loadPeak Amplitude (V ) = 220Vin R = 2?L = .01Hf = 50 Hz 0 Firing angl..

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  • "Power ElectronicsSimulation Assignment Analysis of Single-phase fully-controlled bridge rectifier feeding an R-L loadSingle-phase fully-controlled bridge rectifier feeding an R-L loadPeak Amplitude (V ) = 220Vin R = 2?L = .01Hf = 50 Hz 0 Firing angle =30 SOURCE VOLTAGEOUTPUT VOLTAGE (Vo)0 We are firing at 30 so source voltage appears across the Load. Due to the presence of Inductor which gets charged0 0 during positive half cycle the devices remain forward biased even after 180 . So the devices conduct till 210 due to theinductance stored energy when other pair of Devices is fired.DEVICE VOLTAGE ( Vd )Initially all 4 devices are off so voltage distributed across T2 and T2’ equally so the voltage across the device is Vs/2.0 When we turn on T1 and T1’ then voltage across T2 becomes equal to Vs so there is a jump at 30 in the voltage acrossT2.After it current is continuous so one pair of devices must conduct so this will not happen. SOURCE CURRENT(I )SWhen commutation occurs then SOURCE CURRENT reverses its Direction.LOAD CURRENT (Io)LOAD VOLTAGE AND I*R0 We are firing at 30 so load current starts increasing slowly due to the inductive Load till it reaches its peak when(I*R=Vo) as shown in above figure. Then Inductance will release its energy and current will decrease till the next pair ofdevices is fired. The current took 3 cycles to attain its steady state value as clear from above fig. 0THD FOR firing angle 30 THD=.2559Total Harmonic Distortion gives a measure of the deviation of the waveform from its fundamental. The high value ofTHD is justified as the waveform is highly distorted with respect to a sinusoid of frequency 50Hz.0 Firing angle =60R=2?L=0.01H0 Therefore power factor angle is 57 . 0 So at firing angle 60 there is discontinuous conduction.SOURCE VOLTAGE (Vs)OUTPUT VOLTAGE ( Vo )Due to Discontinuous conduction output voltage becomes zero for a short time when none of the devices areconducting then it again equal to source voltage. DIODE VOLTAGE(Vd)Due to Discontinuous conduction output voltage becomes Vs/2 for a short time when none of the devices areconducting then it again equal to source voltage.OUTPUT LOAD CURRENT (Io) "

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