Work done to take a particle of mass, Physics

What is the work done to take a particle of mass m from surface of the earth to a height equal to 2R (R=radius of earth )?

Ans) Initial PE= - GMm/R

Final PE = - GMm/3R

Change in PE=Work Done=  2GMm/3R (ANS.) 

 

 

Posted Date: 4/5/2013 1:38:41 AM | Location : United States







Related Discussions:- Work done to take a particle of mass, Assignment Help, Ask Question on Work done to take a particle of mass, Get Answer, Expert's Help, Work done to take a particle of mass Discussions

Write discussion on Work done to take a particle of mass
Your posts are moderated
Related Questions
Subtracting 2 Vectors This is where things obtain a bit more interesting. What we required to note here is in which in Physics a negative sign simply means "in the opposite dir

Write the relation for the force acting on a charge carrier q moving with a velocity by a magnetic field in vector notation. Using this relation, reduce the conditions under which

Two forces have magnitudes of 11 newtons and 5 newtons. The magnitude of their sum could NOT be equal to which of the following values? a) 16 newtons b) 5 newtons b)

What will be effect on radius Newton''s rings if air is replaced by oil between the lens and the glass plate


What are the pumping schemes? Pumping Schemes: a. Optical pumping through photons b. Electrical pumping through electric glow discharge/electric current/electron beam

Steelyards Either Roman or Danish steelyards can be improvised using short lengths of lead or iron water pipe as counter-weights and loops of wire s pivots. The rod can be o

Q. What is a capacitor? Define: capacitance. i) A capacitor is a apparatus for storing electric charges. ii) The capacitance of a conductor is defined like the ratio of the

Q. A 4.5cm needle is placed 12cm away from a convex mirror of focal length 15cm. Give the location of the image and the magnification. Describe what happens as the needle is moved

Q. State Coulombs law in electrostatics? Coulomb's law declares that the force of attraction or repulsion between two point charges is directly proportional to the product of t