Here we will use the expansion method Firstly lim_{x-0 }log_{a}(1+x)/xfirstly using log property we get:lim_{x-0}log_{a}(1+x)-logxthen we change the base of log i.e lim_{x-0} {log_{e}(1+x)/log_{e}a}-log_{a}xthen adter using expansion of log_{e}(1+x) we get answer " 1/log_{e}a