sin(2x+x)=sin2x.cosx+cos2x.sinx

             =2sinxcosx.cosx+(-2sin^2x)sinx

             =2sinxcos^2+sinx-2sin^3x

            =sinx(2cos^2x+1)-2sin^3x

=sinx(2-2sin^2x+1)-2sin^3x

           =2sinx-2sin^3x+sinx-2sin^3x

                                            = 3sinx-4sin^3x

Posted Date: 3/9/2013 4:53:12 AM | Location : United States

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