Trans power and channel loss, Science

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Trans power : 20dBm
Channel loss = 60dB
We know that
Received power (dBm) = Tx Power (dBm) + Tx Antenna Gain (dBi) + Rx Antenna Gain (dBi) - loss (db) as Tx and Rx antenna gains are not mentioned we may assume that those are 0 so we have

received power (dbm) = 20 dBm - 60dB = -40 dBm this shows that condition (a) is satisfied

We have noise power at receiver = 10^-9W = 10^-6 mW and as dBm = log (mW) * 10

the noise power at receiver in dbm = 10xlog 10-6 = -60 dbm we also know

SNR(dB) = Received power (dbm) - noise power (dbm)
= -40 - (-60) = 20 dB

Thus condition (b) is also satisfied. As both the conditions are satisfied the receiver will not face any problem in receiving frames.


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