Car travelling 60 km per hour Overtakes another car travelling at 42km per hour. Asuming each car to be 5metre long . Find totoal time taken during the Overtake. and road distance.
For the car with 60kmph to overtake the first car it should travel a relative distance of 10 m
(5m for catching up and 5m for getting clear ahead)
therefore Srel = 10 m
Vrel = 60-42 = 18km/hr = 5 m/s
Relative acceleration = 0 .since both are moving with constant velocities.
Now using relative motion, S = Vrel × t
therefore time ,t = S / Vrel = 10/5 = 2s
Distance used to overtake is 60 × 5/18 × 2 = 100/3 = 33.33 m