Linear programming , Operation Research

#quesQuestion. a paper mill produces two grades of paper viz.,xand y.Bacause of raw material restrictions, it cannot produce more than 400 tones of grade x paper and 300 tons of grade y paper in a week. there are 160 production hours in a week. it requires 0.25and 0.40 hours to produce a ton of grade z snf y psprtd. the mill earns a profit of rs.200 and rs.500 per ton of grade x and y paper respectively. formulate this as a linear programming problem. tion..
Posted Date: 2/13/2013 8:51:28 AM | Location : USA







Related Discussions:- Linear programming , Assignment Help, Ask Question on Linear programming , Get Answer, Expert's Help, Linear programming Discussions

Write discussion on Linear programming
Your posts are moderated
Related Questions
Scope of operation research?

The manufacturer of the product is finding that, in order to stay competitive, a number of things need to happen: Components of the product need to be made from more sustaina

A paper mill produces two grades of paper viz., X and Y. Because of raw material restrictions, it cannot produce more than 400 tons of grade X paper and 300 tons of grade Y paper i

A paper mill produces two grades of paper viz X and Y. Because of raw material restrictions, it cannot produce more than 400 tons of grade X paper and 300 tons of grade Y paper in

LIMITS OF TRANSPOTATION PROBLEM

DECILES The nine points  on the scale of observations  ( or  values of the variable) which divide the total  frequency into ten  equal parts  are called deciles for the data

Regression Line The line  of regression  is the  line  which give the best  estimate  to the  values  of one  variable  for any  specific  values  of other  variable. For t


Method of Calculation of Mean  Deviation a. Computation of Mean Deviation Individual Series : The process of computing mean  deviation in case  of individual series involves

Solve the following Linear Programming Problem using Simple method. Maximize Z= 3x1 + 2X2 Subject to the constraints: X1+ X2 = 4 X1 - X2 = 2 X1, X2 = 0