Three times the larger of the two numbers, Mathematics

If three times the larger of the two numbers is divided by the smaller, then the quotient is 4 and remainder is 5. If 6 times the smaller is divided by the larger, the quotient is 4 and remainder is 2. Find out the numbers.

Posted Date: 3/18/2013 7:29:03 AM | Location : United States







Related Discussions:- Three times the larger of the two numbers, Assignment Help, Ask Question on Three times the larger of the two numbers, Get Answer, Expert's Help, Three times the larger of the two numbers Discussions

Write discussion on Three times the larger of the two numbers
Your posts are moderated
Related Questions
Write a script to determine the volume of a pyramid, which is 1/3 * base * height, where the base is length * width.  On time the user to enter values for the length, width, and th

Q. What is Common Triangles? Ans. Some triangles appear more commonly than others. You will come across two triangles repeatedly as you learn more about trigonometry. T

Solve the Limit problem as stated  Limit x tends to 0 [tanx/x]^1/x^2 is ? lim m tends to infinity [cos (x/m)] ^m is? I need the procedure of solving these sums..

Let a 0 , a 1 ::: be the series recursively defined by a 0 = 1, and an = 3 + a n-1 for n ≥ 1. (a) Compute a 1 , a 2 , a 3 and a 4 . (b) Compute a formula for an, n ≥ 0.

a boy is six months old his sister was given birth to three month after him. if their cousin is 0.33years old, arrange their ages in ascending order

verify liouville''s theorem for y''''''-y''''-y''+y=0

how to Multiplying Rational Expressions ? To multiply fractions, or rational expressions, you must multiply the numerators and then multiply the denominators. Here's how it is

Simplify following and write the answers with only positive exponents.  (a) ( x 8.2 y -0.26 z 2 ) 0.5  (b)  (x 3 y -4.1   / x -2.7 ) -3 Solution  (a) (x 8.2

using a pair of compasses a ruler and a pencil. construct a triangle CDE in which DE=10cm, DC+8cm and CDE= 45 degrees. construct CF perpendicular to DE such that F lies on DE using

Solve by factorization X 2 +(a/a+b + a+b/a)x+1 = 0 X 2 +(a/a+b + a+b/a)x+1 =>  X 2 +(a/a+b x a+b/ax + a/a+b .a+b/a) =>  X[x+a/a+b] +a+b/a[a+a*a+b]= 0 =>  X= -a