Thermodynamics, Chemistry

Calculate the free energy change of following reaction at298 kelvin H2+I2=2HI if the enthalpy change is 51.8816kj and the entropy change is 166.15j is this reaction thermodyanamically possible?

Solution) delta g=51.8816kj-298*166.15/1000kj

delta g=2.3689

since delta g is +ve therefore this reaction is not themodynamically possible

Posted Date: 3/11/2013 12:35:33 AM | Location : United States





Free energy change=enthalpy change-298(entropy change)

reaction is thermodynamically possible if free energy change is negative.

Posted by | Posted Date: 3/11/2013 12:35:54 AM


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