The ph of an aqueous solution of ba(oh)2, Chemistry

The ph of an aqueous solution of Ba(OH)2 is 10 if the ksp of Ba(OH)2 is 1*10^-9 then the concentration of Ba+2 ions in the aqueous solution is

 

Ans) [OH(-)] = 10^(-4)

2.[OH(-)] = 2*10^(-4)

Ba(OH)2 <=> Ba(2+) + 2.OH(-)

Ksp=10^-9

so,

[Ba(2+)].(2.10^-4)^2 = 10^-9

[Ba(2+)] = 0.25 * 10^-1 (Ans)

 

 

Posted Date: 4/5/2013 1:00:06 AM | Location : United States







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