How many integers satisfy (sqrt n- sqrt 8836)^2<1? Solution) sqrt 8836 = 94 , let sqrt n=xthe equation becomes...(x-94)^2 < 1(x-94)^2 - 1 < 0(x-95)(x-93) < 0hence 938649 < n < 9025 the number of integers are 9024-8650+1=375
Hence the number of Integers are 375 (ANS).