Sqrt n- sqrt 8836, Mathematics

  How many integers satisfy (sqrt n- sqrt 8836)^2<1?

Solution) sqrt 8836 = 94 , let sqrt n=x
the equation becomes...
(x-94)^2 < 1
(x-94)^2 - 1 < 0
(x-95)(x-93) < 0
hence  938649 < n < 9025
 the number of integers are 9024-8650+1=375

Hence the number of Integers are 375 (ANS).

Posted Date: 3/29/2013 5:40:43 AM | Location : United States







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