Silver has a density of 10.5gcm^{-3 }. The no. of silver atoms on a surface area of 10-12m^{2} can be expressed in scientific notation aas y x 10x.The value of x is ..?
Ans) d = mass/V⇒ 10.5 g/cc means in 1 cc ⇒ 10.5 g of Ag is present.Number of atoms of Ag in 1 cc ⇒ A10.5 N108 ×In 1 cm , number of atoms of Ag 3A10.5 N108=In 1 cm2, number of atoms of Ag2 /3A10.5 N108In 10-12m^{2} or 10-8 cm^{2}, number of atoms of Ag2 / 3 24 2 / 38 8A10.5 N 10 1.05 6.022 10 10108 108= 1.5 × 107Hence x = 7