Results for the underlying problem-conventional priority , Mechanical Engineering

Results for the Underlying Problem

The rules mentioned above and several variants of these rules that became out to be inferior are tested for eight various conditions of the FMS for the production of turbochargers. All these presentation criteria are evaluated for 25 various simulations run and after that averaged. The 25 various simulation runs are produced from five various random basic part type sequences and five various random due date sequences. For a importance analysis of the dissimilarity of two policies, the outcome of all 25 runs was utilized in a Wilcox on test.

Initially, the easy rules were compared. This twisted out that for the three criteria Tmean, Trms, and Tmax and the eight cases identify, the subsequent rules outperformed the others:

(a) ODD best rule along with respect to all criteria under high time pressure;

(b) SL/OPN best rule along with respect to each criterion under low time pressure;

(c) CR best mean and rms tardiness in case 2 under average pressure.

Amongst the combined and split queue rules, the excellent are as:

(a) CR + SPT best rule along with respect to Tmean in all the conditions;

(b) SPT - T r = 0;

(c)    SPT / Sl u = 0;

The last two rules are the best ones along with respect to Tax in all the conditions and along with respect to Trms   under medium and high pressure.  For case 2 under low pressure, CR + SPT offer better results. For the underlying system also, the most complicated rules are outperformed via the easier ones.

Clearly, the identified priority rules for job shop scheduling can be divided in two classes depending upon their behavior under high pressure as:

(a)     Rules that use SPT for critical jobs; and

(b)     Rules that use SL or similar criteria for critical jobs.

The first class of rules attains the best values of Tmean at the cost of high values of Tmax. The second class avoids excessive delays of a minute fraction of the jobs at the cost of a superior value of Tmean. Inside these classes, some rules show a comparable performance. In the initially class, CR + SPT for our problem provided the excellent results; in the second best were ODD and SL/OPN. These three rules generated Pareto optimal results along with respect to the three criteria. In the individual machine case, the Pareto-optimal rules were EDD and MOD that in this case are identical along with ODD respective CR + SPT.

 

Posted Date: 3/5/2013 8:03:36 AM | Location : United States







Related Discussions:- Results for the underlying problem-conventional priority , Assignment Help, Ask Question on Results for the underlying problem-conventional priority , Get Answer, Expert's Help, Results for the underlying problem-conventional priority Discussions

Write discussion on Results for the underlying problem-conventional priority
Your posts are moderated
Related Questions
The turbine rotor of ship of mass 6000Kg has a r of Gyration 50cm. It moves at speed of 1820rpm clockwise when looking from the rear. Evaluate the effects set up:- 1) If the shi

#question.types images.

Explain Principal Process for Abrasive Jet Cutting Machines Abrasive particles are fed from the hopper in to the mixing chamber by regulating device as shown in figure.

Friction: When a body moves or tends to move over the other body, a force opposing the motion develops at the contact surfaces. This force that opposes the movement or the ten

Q. Application of cold service insulation? Cold insulation shall be installed specifically in accordance with the Manufacturer's recommendations, and generally as outlined belo

Three basic types for microbial systems: Porous, nozzle and orifice Porous sparger  Laboratory operation, usually constructed from sintered glass or metal. Disadvantages a

REACTIO N TURBINE: The turbine in which the steam expands while passing over the moving blades as well as while passing over the fixed blades and the pressure of steam dec

Spot welding of different metals-Nickel and monel metal While spot welding these materials, the settings are to be properly maintained. Welding time, in this case, is only 50 %

Discover the suitable diameter of the shaft: A shaft is required to fail while the torque on the shaft is 20 kN-m. Discover the suitable diameter of the shaft of the modulus o

what is the difference between intrinsic and extrinsic process?