By Using the discriminant find out which solution set we obatin for each of the following quadratic equations.
13x^{2} +1= 5x
Solution
Firstly get the equation in standard form.
13x^{2 }- 5x + 1 = 0
Then we have,
a = 13 b = -5 c=1
Plugging in the discriminant gives,
b^{2} - 4ac = ( -5)^{2} - 4 (13) (1) =-27
The discriminant is negative & thus we will have two complex solutions. For reference reason the actual solutions are,