Real distinct solutions, Algebra

By Using the discriminant find out which solution set we obatin for each of the following quadratic equations.

                                          13x2 +1= 5x


Firstly get the equation in standard form.

13x2 - 5x + 1 = 0


Then we have,

a = 13             b = -5 c=1

Plugging in the discriminant gives,

                  b2 - 4ac = ( -5)2  - 4 (13) (1) =-27

The discriminant is negative & thus we will have two complex solutions.  For reference reason the actual solutions are,

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Posted Date: 4/6/2013 5:08:12 AM | Location : United States

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