wht is pumping lema

Posted Date: 9/23/2014 4:50:42 AM | Location : USA

Ask an Expert

Related Discussions:- pumping lema, Assignment Help, Ask Question on pumping lema, Get Answer, Expert's Help, pumping lema Discussions

Write discussion on pumping lema
Your posts are moderated

Write your message here..

Related Questions

Codds rule, What are codds rule What are codds rule

Operations on strictly local languages, The class of Strictly Local Languag... The class of Strictly Local Languages (in general) is closed under • intersection but is not closed under • union • complement • concatenation • Kleene- and positive

Pendulum Swings, how many pendulum swings will it take to walk across the c... how many pendulum swings will it take to walk across the classroom?

Ardens theorem, how is it important how is it important

Kleene Closure, 1. Does above all''s properties can be used to prove a lang... 1. Does above all''s properties can be used to prove a language regular? 2..which of the properties can be used to prove a language regular and which of these not? 3..Identify one

Kleene closure, So we have that every language that can be constructed from... So we have that every language that can be constructed from SL languages using Boolean operations and concatenation (that is, every language in LTO) is recognizable but there are r

Automaton theory, let G=(V,T,S,P) where V={a,b,A,B,S}, T={a,b},S the start ... let G=(V,T,S,P) where V={a,b,A,B,S}, T={a,b},S the start symbol and P={S->Aba, A->BB, B->ab,AB->b} 1.show the derivation sentence for the string ababba 2. find a sentential form

Multiple instruction single data stream, short application for MISD short application for MISD

Abstract model of computation, When we say "solved algorithmically" we are ... When we say "solved algorithmically" we are not asking about a speci?c programming language, in fact one of the theorems in computability is that essentially all reasonable program

Constract Context free, constract context free g ={ a^n b^m : m,n >=0 and n... constract context free g ={ a^n b^m : m,n >=0 and n