Prove the equations using the Boolean algebraic theorems that is given below
A‾BC + AB‾C + ABC‾+ ABC = AB + BC + AC

Ans. The equation given is A‾BC + AB‾C + ABC‾+ ABC = AB + BC + AC
L.H.S = A‾BC + AB‾C + ABC‾+ ABC
= A‾BC + AB‾C + AB (C +C‾)
= A‾BC + AB‾C + AB (Q C + C‾ = 1)
= A‾BC + A (B + B‾C)
= A‾BC + A (B + C) (? B + B‾C = B + C)
= A‾BC + A B + AC
= C (A + A‾B) + AB + AC
= C (A + B) + A B + AC (? A + A‾B = A + B)
= AC + BC + AB + AC
= AB + BC + AC (? AC + AC = AC)
= R.H.S Thus Proved