Projectile-motion, Physics

A particle is projected from ground with velocity 40sqrt2m/s.find- a)velocity and b)displacement of particle after 2sec .Take g=10m/s^2

Ans)
velocity

v=u+at

a=-g

v=40√2-10*2

v=20(2√2-1)m/s

s=ut+at2/2

s=40√2*2-10*2*2

s=80√2-40

s=40(2√2-1)m

 

 

Posted Date: 3/8/2013 6:32:33 AM | Location : United States





given velocity v=40 root 2

v=u+at where a=g

1.v=u+at====>

we have to get the value by using this formula

2.s=ut+1/2gt^2 by using this formula wehave to get the value of displacements

Posted by | Posted Date: 3/8/2013 6:33:57 AM


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