Possible outcome of a coin - probability based question, Mathematics

A coin is tossed twice and the four possible outcomes are assumed to be equally likely. If A is the event,  both head and tail have appeared , and B be the event at most one tail is observed  find

P(A/B)

A) 1/3      B) 2/3     C) ½    D) ¼

Here, S={HH,HT,TH,TT},A={HT,TH} and B={HH,HT,TH,}

A∩B={HT,TH}

Now(A)=n(A)/n(s)=2/4=1/2,P(B)=n(B)/n(S)=3/4

And (A∩B)=n(A∩B)/n(S)=2/4=1/2

P(A/B)=P(A∩B)/P(B)=1/2/3/4  = 2/3.

Posted Date: 7/23/2012 3:29:13 AM | Location : United States







Related Discussions:- Possible outcome of a coin - probability based question, Assignment Help, Ask Question on Possible outcome of a coin - probability based question, Get Answer, Expert's Help, Possible outcome of a coin - probability based question Discussions

Write discussion on Possible outcome of a coin - probability based question
Your posts are moderated
Related Questions

Excuse me, would you give me main points on prime ideals to do project

WHAT TWO SIX DIDGIT NUMBERS CAN YOU ADD 984,357

altitude 35000 @ 9:30 9;42 alt 17500 increase speed by factor of 3 level out at 2500= how much time will it take


Integral Test- Harmonic Series In harmonic series discussion we said that the harmonic series was a divergent series.  It is now time to demonstrate that statement.  This pr

explain how business mathematics in an inbu;it component of a payroll package

i need help trying make a presentation for my teacher

how can i solve a multi variable power regression equation..? EX: y=a*(x1^b)*(x2^c).... i need to solve with 4 variable....

A train covered a certain distance at a uniform speed.  If the train would have been 6km/hr faster, it would have taken 4hours less than the scheduled time.   And if the train were