Permatuation and combination problem, Mathematics

A,B,C are natural numbers and are in arithmetic progressions and a+b+c=21.then find the possible values for a,b,c

Solution) a+b+c=21

a+c=2b

3b=21

b=7

a can be 1,2,3,4,5,6

c can be 13,12,11,10,9,8 

Posted Date: 3/11/2013 7:12:05 AM | Location : United States







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