padovan string, C/C++ Programming

padovan string generation till 40
Posted Date: 9/2/2012 2:12:53 AM | Location : United States





program 1 :
package test.padovanstring;

public class PadovanString {
public int stringOccurrences(int n, String str){

if(n >= 40)
return -1;
if(str.replaceAll("X|Y|Z","").length()>0)
return -1;
String res=pad(n);
return(res.length() - res.replaceAll(str,"").length())/(str.length());
}
public String pad(int n){
if(n == 0) return "X";
if(n == 1) return "Y";
if(n == 2) return "Z";
else return pad(n-2) + pad(n-3);

}
public static void main(String []args)
{
PadovanString p = new PadovanString();
System.out.println(p.stringOccurrences(21,"YZ"));
}
}



Program set 2 :
import java.util.Scanner;
import java.util.ArrayList;

public class PadovanSeries
{
public static void main(String[] arg)
{
Scanner read = new Scanner(System.in);
System.out.println("Enter starting no. : ");
int start = read.nextInt();
System.out.println("Enter ending no. : ");
int end = read.nextInt();
int[] ans = getSeries(start, end);
System.out.println("Padovan series : ");
for (int a : ans)
System.out.print(a + " ");
}

public static int[] getSeries(int s, int e)
{
ArrayList list = new ArrayList();
int i, j = 0;
for (i = s; i <= e; i++, j++)
list.add(getPadovan(i));
int[] ans = new int[j];
for (i = 0; i < j; i++)
ans[i] = list.get(i);
return ans;
}

public static int getPadovan(int p)
{
if (p == 0 || p == 1 || p == 2)
return 1;
return (getPadovan(p - 2) + getPadovan(p - 3));
}
}

Padovan String
Problem Description
A Padovan string P(n) for a natural number n is defined as:

P(0) = ''X''

P(1) = ''Y''

P(2) = ''Z''

P(n) = P(n-2) + P(n-3), n>2
where + denotes string concatenation.
For a string of the characters ''X'' , ''Y'' and ''Z'' only, and given value of n, write a program that counts the number of occurrences of the string in the n-th Padovan string P(n).

An example is given below.

For n = 6 and the string ZY, the program should count the occurrences of ZY in P(6).

P(0) = ''X''

P(1) = ''Y''

P(2) = ''Z''

P(n) = P(n-2) + P(n-3), n>2


P(3) = P(1)+P(0)

P(3) = YX


P(4) = P(2)+P(1)

P(4) = ZY


P(5) = P(3)+P(2)

P(5) = YXZ


P(6) = P(4)+P(3)

P(6) = ZYYX

So, the number of occurrences of the string ZY in P(6) is 1.
Instruction to work with Open PBT Client:

Specify the work directory path in the ''Work Directory Path'' field. The path should correspond to your solution project directory.
Download the support files by clicking the Get Dev Files.
You will find the following three folders:
bin
src
lib
in your work directory.
Code the solution in . java file inside the src folder
All required files will be downloaded to your work directory. Creating additional files is strongly discouraged.

Step 1:
In your solution file:

Implement your logic in public int stringOccurrences(int n, String str) in class PadovanString.
int n: n is an integer represents n(th) for which full main string has to formed, from which occurrence of string str has to be found.
String str : str is a string represents sub string whose occurrence has to be found in the main string.

You can create more methods but, do it in the same class.

Step 2:
In your solution keep in mind the following constraints:.

In this problem you have to write a program that counts the number of occurrences of the string in the n-th Padovan string P(n).
Padovan formula is P(n) = P(n-2) + P(n-3) where n>2 and n is the integer.
In the above Padovan formula + sign means string concatenation.
For the Padovan formula value of P(0),P(1) and P(2) is given. You have to use those value only.
n should not be greater than 40 otherwise return -1
string str should be consist of only X,Y and Z in upper case otherwise return -1

The Prototype of the method is:
public int stringOccurrences(int n, String str).
This method takes following arguments.

n is the value for which full main string has to formed, from which occurrence of string str has to be found.
str represents sub string whose occurrence has to be find in the main string.

This method returns a number of occurrence of string str in the main string.

The constraints are:

n should not be greater than 40 otherwise return -1
string str should be consist of only X,Y and Z in upper case otherwise return -1

Example 1
Input :
int n = 6
string str = ZY
Output :
1
Explanation : This question is explained in problem description.
Example 2
Input :
int n = 6
String str = ZYmm
Output :
-1
Explanation :
String str is containing character other than X, Z and Y.
Example 3
Input :
int n = 8
String str = XZ
Output :
Posted by diana | Posted Date: 9/4/2012 4:15:58 AM


Related Discussions:- padovan string, Assignment Help, Ask Question on padovan string, Get Answer, Expert's Help, padovan string Discussions

Write discussion on padovan string
Your posts are moderated
Related Questions
Raj is a newbie to the programming and while learning the programming language he came to know the following rules: · Each program must start with ''{'' and end with ''}''. Ã

count the number of string in n-th padovan string

pls say code for this above..

The procedure +, * and list take arbitrary numbers of arguments. One way to define such a procedure is to use define with dotted-tail notation. In a procedure definition, a paramet

overloadstream insertion opertator to display the data of object on the console

Define Static Storage Class in C Programming? The Static declarations have distinct and important uses. This allows the local variable to keep its previous value when the block

need to create c++ classes to store all pascal types in compiler design.

- But with less features and more user-friendly (particularly for non-tech savvy users). - Software needed having a left menu with links (no pictures required) for every hardwar

Need help with C network program

A: No. There is nothing you can do in C++ which you cannot do in C. In spite of everything