A car travels along a horizontal circular curved road that has a radius of 600 m. If the speed is uniformly increased at a rate of 2000 km>h2, determine the magnitude of the acceleration at the instant the speed of the car is 60 km>h.
Ans) a^{2}=(a_{r})^{2}+(a_{t})^{2}
a^{2}=v^{2}/r+(2000km/hr^{2})^{2}
a^{2}=36000000+4000000
a=6.32*10^{3}
a^{2} = (v^{2}/r)^{2} + a_{T} = (3600/0.6)^{2 }+ (2000)^{2} = (6000)^{2} + (2000)^{2} = 40*10^{6}
a≈6.32*10^{3} km/h^{2}