Magnetic alloy steels, Mechanical Engineering

Magnetic Alloy Steels:

These steels are divided into two sets. Such which retain their magnetism and that which do not. The steels which retain their magnetism are termed as hard magnetic steels. The other group is magnetically soft.

1 percent plain carbon steel in its entirely hardened situation was the earliest permanent magnetic material. Later improvements occurred whilst W, Cr and cobalt were added like alloying elements. The most helpful of permanent magnetic steels contain high proportions of Nickel, Co, and Al, along with small amount of W. Alnico is an excellent example that comprises 10% Al, 18% Nickel, 12% Co, 6% Copper, Rest Fe.

Magnetically soft materials are needed to demagnetise rapidly. In prior days soft iron was utilized as a soft magnetic material but later iron-silicon alloys containing upto 4.5 percent Si were improved. Though, modern high duty soft magnetic materials are iron-nickel alloys as like: Permalloy that contains 78 percent Ni. Another soft magnetic material is mumetal having 75% Ni. These alloys are employed for transformer cores and as shield material for submarine cables.

Alloy steels calculate a wide range of application and a few of them are explained in Table.

Table: Application of Alloy Steels

Sl. No.

Application

Desired Properties

Composition (% )

1

Rail steel

Strength, ductility, impact and fatigue strength

C - 0.4 to 0.6 Mn and

Cr - upto 1

2

Spring steel (tension compression, torsion)

Good elongation high elastic limit (20 to 30%, 1200-1400 MPa). Good surface finish for fatigue strength

(a) C - 0.6, Mn - 0.9, Si - 2.0

(b) C - 0.5, Mn - 0.8, Cr - 1.0, V - 0.15

(c) C - 0.5, Ni - 0.9, Cr - 0.5, Ni - 0.6, Mo - 0.2

3

Structural steel (bridges, building, cars, gears, clutches, shafts)

High strength, toughness, high temperature strength, corrosion resistance

Wide range of alloy steels containing several alloying elements

4

Weldable steel for welded structures

Weldability, high resistance to atmospheric corrosion, resistance to brittle fracture

C - 0.15 to 0.3 with some

Cu and V

5

Concrete reinforcing steel

Bend 90o - 180o, tor-steel with ribs for greater surface area.

Elongation = 16%, UTS = 500-650 MPa, Y. S. = 35 MPa.

Elongation = 13%,

UTS = 600 MPa, Y. S. = 350 MPa

C - 0.3 to 0.4, Mn - 0.5 to 0.8

 

 

C - 0.45 to 0.6, Mn - 0.7 to 1.1

6

High speed steel for cutting tools

Resist temperature upto

550-600oC. Cutting tools requiring high hardness at working temperature 18 : 4 : 1 steel and

6 : 5 : 4 : 2 steel

C - 0.8, W - 18, Cr - 4, V - 1,

C - 0.8, W - 6,

Mo - 5, Cr - 4, V - 2

7

Creep resisting steel

Application in pipelines upto

400-550oC. Other parts upto

550oC

Mo - 0.4 to 6

V - 0.25 to 1.0

Cr - upto 6.0, C - low

8

Hadfield Mn steel, excavating and crushing m/c. rail road crossing, oil well, cement, mining industries. Used as casting and hot rolled

Resistance to abrasion and shock, high toughness strength and ductility

C - 1 to 1.4,

Si - 0.3 to 1.0, Mn - 10 to 14

9

High strength low alloy steel (HSLA) for automotive parts

High strength/weight ratio. Balanced properties such as toughness, fatigue strength, weldability and formability

C - 0.07 to 1.3, Ti, V, Al, Co less than 0.5

10

Ball bearing steel

Rolling element, inner and outer races. High hardness

61-65 Rc high fatigue strength

C - 0.9 to 1.1, Cr - 0.6 to 1.6, Mn - 0.2 to 0.4

Posted Date: 2/26/2013 6:40:14 AM | Location : United States







Related Discussions:- Magnetic alloy steels, Assignment Help, Ask Question on Magnetic alloy steels, Get Answer, Expert's Help, Magnetic alloy steels Discussions

Write discussion on Magnetic alloy steels
Your posts are moderated
Related Questions
Write a report on the procedure along with the MATLAB code. The subject is Gas Dynamics

Coplanar and Non-Coplanar Forces: In this unit, you have learnt to identify the different systems of forces. You have also learnt the many techniques of adding the forces to g

series shaft and parallel shaft

Following sets of the three forces act on a body,. In which case resultant cannot be zero? 1) 10N, 10N, 10N 2)10N, 10N, 20N 3)10N, 20N, 20N 4010N, 20N, 40N Ans)      In 4th

determine the shear force and bending moments of 4KN fprce

A semi elliptical spring has 10 leaves in all, with the two full length leaves extending 625 mm. It is 62.5 mm wide and is prepared by strips 6 mm thick. Prepare a design of helica


The following guidelines are intended to assist the HVAC lead, designer or auditor in preparing an assessment of the quality of the HVAC engineering work for a specific project. T

Find out the centre of gravity of solid sphere: Find out the C. G. of a body formed by a solid sphere placed over a solid cylinder of similar radius a as illustrated in Figure

Illustrate the following terms:- a) Mechanism and Inversion b) Slip and Creep of belt drive c) Centrifugal Tension of belt drive d) Initial Tension of belt drive