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sin (cot -1 {cos (tan -1 x)}) tan -1 x = A  => tan A =x sec A = √(1+x 2 ) ==>  cos A = 1/√(1+x 2 )    so   A =  cos -1 (1/√(1+x 2 )) sin (cot -1 {cos (tan -1 x)}) = s

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Above we have seen that (2x 2 - x + 3) and (3x 3 + x 2 - 2x - 5) are the factors of 6x 5 - x 4 + 4x 3 - 5x 2 - x - 15. In this case we are able to find one facto

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Solve the subsequent differential equation. 2xy - 9 x 2 + (2y + x 2 + 1) dy/dt = 0 Solution Let's start off via supposing that wherever out there in the world is a fun

I need help with pre algebra in 5th grade intermidate school math until Tuesday afternoon please