Inverse cumulative distribution function, Applied Statistics

The Null Hypothesis - H0: β0 = 0, H0: β1 = 0, H0: β2 = 0, Βi = 0

The Alternative Hypothesis - H1: β0 ≠ 0, H0: β1 ≠ 0, H0: β2 ≠ 0, Βi ≠ 0      i =0, 1, 2, 3

Reject H0 if |t | > t?¹             = 1.96155 or Reject H0 when P-value ≤ α = 0.05

 

Predictor         Coef     SE Coef       T      P    VIF

Constant       0.37593     0.01341   28.04  0.000

totexp     -0.00131710  0.00005581  -23.60  0.000  1.045

age          0.0016462   0.0003019    5.45  0.000  1.038

nk            0.031672    0.004676    6.77  0.000  1.007

Inverse Cumulative Distribution Function

Student's t distribution with 1499 DF

P( X <= x )        x

      0.975  1.96155

Since the constant = 28.04 > 1.96155 (CV) and the P-Value is ≤ α = 0.05, H0 would be rejected as there is sufficient evidence.      

Since the totexp = -23.60 < 1.96155 (CV) and the P-Value is ≤ α = 0.05, there is evidence to suggest that H0 should be accepted according to the T value however the P-Value suggest otherwise but it is not significant.

Since the age = 5.45 > 1.96155 (CV) and the P-Value is ≤ α = 0.05, H0 would be rejected as there is sufficient evidence.      

Since the nk = 6.77 > 1.96155 (CV) and the P-Value is ≤ α = 0.05, H0 would be rejected as there is sufficient evidence.

Posted Date: 3/5/2013 4:30:10 AM | Location : United States







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