To prove ‾P (1) = pn
Solution: since in the above case we determine each term excluding Bn,n (u) will have numerous of (1 - u)i (i = 0 to n) consequently by using u = 1 will lead to outcome = 0 of all terms except of Bn, n (u).
Bn,n(u) = n!(n!(n-n)!). un .(1 -u)n - n = un
P(u - 1) = p0.0 + p1.0 + .............+ pn.1n