Trignometric function, Mathematics

If tanx+secx=sqr rt 3, 0

Ans) sec2x=(√3-tanx)2

1+tan2x=3+tan2x-2√3tanx

2√3tanx=2

tanx=1/√3

x=30degree

 

Posted Date: 3/8/2013 7:29:36 AM | Location : United States





squaring both the sides,

tan2x + sec2x +2tanxsecx = 3

put sec^2x = tan2x +1

and take 2tanx common,

2tanx(tanx+sec)=2

sqrrt3(tanx)=1

therefore tanx = 1/rt3

x=30

Posted by | Posted Date: 3/8/2013 7:32:19 AM


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