If tana+sina=m and tana-sina=n, show that m2-n2 = 4mn, Mathematics

If tanA+sinA=m and tanA-sinA=n, show that m2-n2 = 4√mn

Ans:    TanA + SinA = m       TanA - SinA = n.

m2-n2=4√mn.

m2-n2= (TanA + SinA)2-(TanA - SinA)2

= 4 TanA SinA

RHS 4√mn  = 4   1111_tan.png

1015_equation.png

= 4 sin2A/cos2 A = 4Tan A sin A

m2-n2=4√mn

Posted Date: 4/9/2013 1:18:31 AM | Location : United States







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