If tan2x.tan7x=1 , than what is the value of tan3x? , Mathematics

tan9x = (tan7x + tan2x)/(1 - tan7x*tan2x)

here its given

1 - tan2x*tan7x= 0

implies

tan9x = infinity

since

tan9x = (3tan3x - tan^3(3x))/(1 - 3tan^2 (3x)) = infinity

implies

1- 3tan^2(3x) = 0

implies

tan3x = 1/sqrt(3). #question..

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