A machine gun fires a bullet of mass 40 g with a velocity 1200 m/s  The man holding it, can exert .  a maximum force of 144 N on the gun. How many bullets can he fire per second at the most?
 
Solution)  According to newtons 2nd law..... F=m(v-u)/t

144=0.04*n*1200/1           (per second...so t=1s)

n=3 bullets / sec

Posted Date: 3/12/2013 2:46:45 AM | Location : United States

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He force exerted by machine gun on man''''s hand in firing a bullet = change in momentum per second on a bullet or rate of change of momentum =(40/1000*)1200= 48 N . The force exerted by man on machine gun = 144 N Therefore, number of bullets fired =  3 Posted by | Posted Date: 3/12/2013 2:47:18 AM

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