How can one "reopen" std::cin & std::cout in binary mode?, C/C++ Programming

A: It is implementation dependent. Verify with your compiler's documentation. For instance, assume you wish to do binary I/O using std::cin & std::cout.

Unluckily there is no standard method to cause std::cout, std::cin and/or std::cerr to be opened in binary mode. Closing the streams and trying to reopen them in binary mode may have undesirable or unexpected results.

On systems where this makes a difference, the implementation may provide a way to make them binary streams; however you would have to verify the implementation specifics to determine out.

 

Posted Date: 3/21/2013 7:44:37 AM | Location : United States







Related Discussions:- How can one "reopen" std::cin & std::cout in binary mode?, Assignment Help, Ask Question on How can one "reopen" std::cin & std::cout in binary mode?, Get Answer, Expert's Help, How can one "reopen" std::cin & std::cout in binary mode? Discussions

Write discussion on How can one "reopen" std::cin & std::cout in binary mode?
Your posts are moderated
Related Questions
full coding for lcm in c++

#At a shop of marbles, packs of marbles are prepared. Packets are named A, B, C, D, E …….. All packets are kept in a VERTICAL SHELF in random order. Any numbers of packets with the


how much is it to fix a small data struct in a sorted list that pass itemtypes. all the code is written just logical errors

Both malloc & new functions are utilized for dynamic memory allocations & the basic difference is: malloc need a special "typecasting" while it allocates memory for eg. if the poin

write a program in c/C++ using nested if statement for calculating the average marks and grades of 5 subjects

Implement multiple stacks in a single dimensional array. Write algorithms for various stack operations for them.

Write a program called A1Q3, that reads it the radius of a circle as an integer and prints the circle's diameter, circumference and area.  Use a constant value for pi.  Do all calc


A Padovan string P(n) for a natural number n is defined as: P(0) = ‘X’ P(1) = ‘Y’ P(2) = ‘Z’ P(n) = P(n-2) + P(n-3), n>2 where + denotes string concatenation. For a string of t