High level language - third generation language , Electrical Engineering

High Level Language ( third Generation Language )

The difficulties of low  level  languages are overcome  by high  level languages. In  assembly  language  mnemonics  were used for  each  statement  of machine  language.  Since  a translator was required to convert an assembly language program  to machine  language  better  translators were   designed for HLL. In high  level  language  we  write  program using.  English like words   instead of mnemonics. The instructions of HLL are called  statements. One statement  of HLL may be  equivalent to many  machine code  instructions. Many  language  are available  in the software  market. The example of few high level  languages are FORTRAN, COBOL PASCAL BASIC C etc, two  type of translators are  used in high  level  language called  interpreter and compiler.

Posted Date: 4/4/2013 1:25:43 AM | Location : United States







Related Discussions:- High level language - third generation language , Assignment Help, Ask Question on High level language - third generation language , Get Answer, Expert's Help, High level language - third generation language Discussions

Write discussion on High level language - third generation language
Your posts are moderated
Related Questions
how does a colpitts oscillator works an also explain the principle


CMA Complement Accumulator  Instruction Complement the  contents of the accumulator  i e the   accumulator  al once are converted zeros  and all zeros  are converted to  ones.

Devise a "green" design to improve the electrical plan of a room in your home. How might you reduce electricity use in your home. Initiate and plan 1. Select two rooms in y

DC chopper This is  one stage  conversion  device  which is used for direct conversion of fixed  de voltage at a level to an adjustable dc voltage  at another  level.


For large number of measurements the mean is calculated by taking a sample. Each sample that is taken has a mean. The mean of various sample difference from sample and are known to

Q For a parallel-plate capacitor with plates of area A m 2 and separation d m in air, the capacitance in farads may be computed from the approximate relation Compute the a

how should I calculate inverse z transform of 1/0.729z^-1+0.729z+1.5314