Friction, Physics

A thin rod of length 1 m is fixed in a vertical position inside a train, which is moving horizontally with

constant acceleration 4 m/s2. A bead can slide on the rod, and friction coefficient between them is 1/2.

If the bead is released from rest at the top of the rod, find the time when it will reach at the bottom.

Solution) If mass of bead is m;

mg-µN=ma

Now, N=pseudo force due to acceleration of train, which is equal to 4m Newton.

 =>   mg-µ(4m)=ma

=>  g-4µ=a

=>  a=8ms-2

 

Using, second equation of motion:

1=0.5(8)t2

T=0.5sec

 

Posted Date: 3/11/2013 12:44:42 AM | Location : United States







Related Discussions:- Friction, Assignment Help, Ask Question on Friction, Get Answer, Expert's Help, Friction Discussions

Write discussion on Friction
Your posts are moderated
Related Questions
Average and Instantaneous Acceleration: Average acceleration is explained as the change in velocity   over a given time interval. As, The instantaneous acceleration of g

Electrostatic field is caused by stationary charge, Induced field is caused by time-varying magnetic field

What occures to the normal shift when the thickness of the optical medium is decreased? Write down the expression for equivalent focal length of combination of two thin lenses d

What are fibers optics made of? For visible light or lighting purposes spectrum transmission, several types of fibers are used. Glass in very suitable strands which have to be

Advantages of high transmission voltage  A) Decreases volume of conductor material: B) Enhance in transmission efficiency C) Reduces percentages line drop

Car travelling 60 km per hour Overtakes another car travelling at 42km per hour. Asuming each car to be 5metre long . Find totoal time taken during the Overtake. and road distance.



Echo vs. Reverberation Sound is a mechanical wave that travels by a medium from a single location to other. This motion by a medium occurs as one particle of the medium interac

Depending upon the penetration power, there are two parts of X-rays Hard X-rays More penetration power More frequency of the order of ≈ 1019 Hz Lesser wavelength range