## Find the sum of all 3 digit numbers which leave remainder 3, Mathematics

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Find the sum of all 3 digit numbers which leave remainder 3 when divided by 5.

Ans:    103, 108..........998

 a + (n-1)d = 998 ⇒ 103 + (n-1)5 = 998 ⇒ n = 180

S180  = 180/2 [103 + 998]

= 90 x 1101

S180 =    99090

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