Find the sum of all 3 digit numbers which leave remainder 3, Mathematics

Find the sum of all 3 digit numbers which leave remainder 3 when divided by 5.

Ans:    103, 108..........998

 

a + (n-1)d

=

998

103 + (n-1)5

=

998

n

=

180

S180  = 180/2 [103 + 998]

= 90 x 1101

S180 =    99090

 

Posted Date: 4/8/2013 5:22:45 AM | Location : United States







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