Find the sides of the two squares, Mathematics

The sum of areas of two squares is 468m2  If the difference of their perimeters is 24cm, find the sides of the two squares.

Ans:    Let the side of the larger square be x.

Let the side of the smaller square be y. APQ x2+y2 = 468

Cond. II          4x-4y = 24

x - y = 6

⇒ x = 6 + y

x2  + y2 = 468

⇒ (6+y)2 +y2 = 468

on solving we get y = 12

x = (12+6) = 18 m

∴ sides are 18m & 12m.

Posted Date: 4/8/2013 3:20:56 AM | Location : United States







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