Find the magnitude of force, Mechanical Engineering

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Find the magnitude of force:

Q: The two parallel forces are acting at point A and B respectively is equivalent to force of 100 N acting downwards at point C and couple of 200Nm. Find the magnitude and force F1  and F2  shown in the figure a.

 

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The given system is converts to single force and single couple at point C. Let R be the resultant of forces F1  and F2.

RH = 0

RV = -F1  -F2

RV = -(F1  + F2)                                                                                                 ...(i)

Since                                          R = (R2v  )1/2  = (F1 + F2)

Let the resultant R act at distance 'd' from point C.

Now the single force that is R is converted in to single force and couple at C

Now apply two equal and opposite force i.e. 'R' at point C. as shown in the figure b. Now force 'R' which act at point E and upward force which act at point C makes a couple of magnitude = Force × distance

                        = R × d

But   R.d = 200 N-m

And force R which is downward direction = 100 N   (negative for downward)

That is, (F1  + F2) = 100 or F1  + F2  = 100                                                                           ...(ii)

Now taking moment about C, or apply varignon's theorem.

R.d = 4F1  + 7F2 , but R.d = 200,

4F1  + 7F2 = 200                                                                                                           ...(iii)

By solving equation (ii)and (iii)

F1 = 500/3 N                                                                             .......ANS

F2 = -200/3 N                                                                          .......ANS


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