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A boy standing on a horizontal plane finds a bird flying at a distance of 100m from him at an elevation of 300. A girl standing on the roof of 20 meter high building finds the angle of elevation of the same bird to be 450. Both the boy and the girl are on opposite sides of the bird. Find the distance of the bird from the girl.
(Ans: 42.42m)
Ans: In right ΔACB
Sin 30 = AC/AB
1/2 = AC/100
2 AC = 100
AC = 50m
⇒ AF = (50 - 20) = 30m
In right Δ AFE
Sin 45 = AF/ AE
1/√2 = 30/AE
AE = 30 √2
= 30 x 1.414
= 42.42m
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