Find the area of the shaded region, Mathematics

ABC is a right angled triangle in which ∠A = 900. Find the area of the shaded region if AB = 6 cm, BC=10cm & I is the centre of the Incircle of ?ABC.

484_circle20.png

Ans: ∠A =900

BC = 10cm; AB = 6cm;
∴ AC = 6cm

Area of the Δ =1/2 x 6 x 8= 24 cm2

Let the Radius of the Incircle be r

∴ 1/2 x 10 x r + 1/2 x 8 x r +1/2 x 6 x r = 24

1/2 r [10 + 8 + 6] = 24

r= 2 cm

∴ Area of circle = Π r2 = 22/7 x 2 x 2 = 88/7 cm2

Area of shaded region = 24 - 88/7 = 168 - 88/7 = 80/7 cm2

Posted Date: 4/10/2013 6:01:26 AM | Location : United States







Related Discussions:- Find the area of the shaded region, Assignment Help, Ask Question on Find the area of the shaded region, Get Answer, Expert's Help, Find the area of the shaded region Discussions

Write discussion on Find the area of the shaded region
Your posts are moderated
Related Questions
Utilizes the definition of the limit to prove the given limit. Solution Let M > 0 be any number and we'll have to choose a δ > 0 so that, 1/ x 2   > M

Spurious Correlations - in several rare situations when plotting the data for x and y we may have a group indicating either positive correlation or negative (-ve) correlation


A student is allowed to select at most n-blocks from a collection of (2n + 1) books. If the total number of ways in which he can select a book is 63, find the value of n. Solution

If the distances from origin of the centres of 3 circles x 2 +y 2 +2alphaix= a 2 (i=1,2,3) are in G.P. , then length of the tangents drawn to them frm any point on the circles x2+

regression line drawn as Y=C+1075x, when x was 2, and y was 239, given that y intercept was 11. calculate the residual

Trace the curve (x/a)^3/2+(y/b)^2/3=1

A patient will receive hemodialysis for 2.5 hours. The amount of fluid removed per hour is 1.4 liters. The total amount removed in liters, will be

An advertising project manager developed the network diagram shown below for a new advertising campagign.  In addition, the manager gathered the time information for each activity,