Find out the velocity of the bullet, Mechanical Engineering

Find out the velocity of the bullet:

A bullet of weight W1  = 5 N is fired into a body B2 of weight W2  = 45 N suspended by a string of length L = 1 metres. Because of impact, body B2 swings through an ∠ θ = 60o. If the impact is fully plastic, find out the velocity of the bullet.

Solution

 Refer Figure. Let initial velocity of the bullet by V1.

 Initial velocity of B2 = V2 = 0

After impact, we have, by principle of conservation of momentum

                                   (m1 + m2) VC = m1 V1            --------- (I)

By using principle of conservation of energy for the second event when body B2 swings through a maximum ∠ θ = 60o,

((W1 + W2) /2 g)(Vc) 2 = (W1 + W2) × L × (1 - cosθ)

∴ V 2  = 2 g L (1/2)   = 9.8 × 1

∴ Vc  = 3.13 m / sec .

Posted Date: 1/29/2013 7:24:00 AM | Location : United States







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