Find out stress - strain and elongation of bar, Mechanical Engineering

Find out stress - strain and elongation of bar:

A circular rod having diameter 20 m and 500 m long is subjected to the tensile force of 45kN. The modulus of elasticity for steel can be taken as200 kN/m2. Find out stress, strain and elongation of bar because of applied load.            

Sol.: Given:

D = 20m

L = 500m

P = 45KN = 45000N

E = 200KN/m2 = (200 × 1000 N/mm2  = 200000 N/m2

By using the relation; σ = P/A  = P/(Π /4 × D2)

σ = 45000/( Π /4 × 202)

σ = 143.24 N/m2                                                                                    .......ANS

E = σ / e

200000 = 143.24 /e

e = 0.000716                                                               .......ANS

Now, e = dLA/L

0.000716 = dLA/500

dLA = 0.36                                                                        .......ANS

Posted Date: 10/20/2012 7:53:17 AM | Location : United States







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