Explain about dihalide, Chemistry

Q. Explain about Dihalide?

Dihalides: Dichlorides and dibromides are formed by the lower members of the group, viz., Se, Te and Po. These are formed mainly by dissociation of the corresponding tetrahalides. Sulphur dichloride can also be formed by chlorination of S2Cl2 preferably, in  presence of a trace of a catalyst such as FeCl,. However, due to the decomposition of S2CI2, into S2Cl2, it is rather unstable. While the dihalides of Se are gaseous, those of Te and Po are solids. These dihalides are hydrolysed by H2O2 according to following equation for TeBr2.

2TeBr2 + 3H2O ---------------> H2TeO3+ 4HBr + Te

Dissolution of chlorine in sulphur monochloride, S2Cl2 gives sulphur dichloride, 9CI2, an  unstable liquid which dissociates back.

Posted Date: 7/8/2013 5:12:02 AM | Location : United States

Related Discussions:- Explain about dihalide, Assignment Help, Ask Question on Explain about dihalide, Get Answer, Expert's Help, Explain about dihalide Discussions

Write discussion on Explain about dihalide
Your posts are moderated
Related Questions
Interconversion of the resonance structures of carbon monoxide with the curved-arrow notation: Because the carbon in the structure on the left has a sextet of electrons, it

why are aromatic nitro compounds pale yellow in colour

How to prepare chemistry assignment on deodrants

can you help me with understanding chemistry?

The boron trihalides are highly volatile; BF 3 (b. p., 173 K) and BCI 3 , (b. p., 260.5 K are gases, BBr 3 a volatile liquid (b. p., 319 K) and Bl 3 a low melting solid (m. p.,

what can be understood from the law of multiple proportions?

Q. Ash content of a foodstuff? Ash content of a foodstuff represents inorganic residue remaining after destruction of organic matter. It may not be the exact measure of the tot

how many blocks of elements are there /define p block elements

Why a covalent bond is directional? The covalent bond is formed as a result of pairing of two electrons in the atomic orbitals of two atoms. The bond then should lie along the