Example of shear force and bending moment diagram, Mechanical Engineering

Example of Shear force and bending moment diagram:

Q: Draw the Shear Force and bending moment diagram for the simply supported beam loaded as shown in the figure given below. 

 

104_Example of Shear force and bending moment diagram1.png

1080_Example of Shear force and bending moment diagram.png

Sol.: Let reaction at support A and B be, RA  and RB  First find support reaction

For that,

1873_Example of Shear force and bending moment diagram2.png

Taking moment about the point A,

ΣMA = 0

2 X 1 + 4 X 2 + 2 X 3 - RB  X 4 = 0

RB = 4KN                                                                                           ...(2)

From equation (1), RA  = 4KN                                                                                                                       ...(3)

Calculation for Shear force Diagram

Draw the section line, here total four section line, which break the load RA and 2KN(Between A and C),

2KN and 4KN(Between C and D),

4KN and 2KN (Between D and E) and

2KN and RB(Between E and B) Consider left portion of beam Take section 1-1

Force on left of section 1-1 is RA

SF1-1 = 4KN (constant value)

Constant value means value of shear force at both the nearest point of section is equal that is

SFA = SFC  = 4KN                                                                               ...(4)

Take section 2-2

Forces on left of section 2-2 is RA  and 2KN

SF2-2 = 4 - 2 = 2KN (constant value)

Constant value means value of shear force at both the nearest point of section is equal that is

SFC = SFD  = 2KN                                                                                                                        ...(5)

Take section 3-3

Forces on left of section 3-3 is RA, 2KN, 4KN

SF3-3 = 4 - 2 - 4 = -2KN (constant value)

The constant value means that value of shear force at both the nearest point of the section is equal that is

SFD = SFE  = -2KN                                                                                                                      ...(6)

Take section 4-4

Forces on left of the section 4-4 is RA, 2KN, 4KN, 2KN

SF4-4 = 4 - 2 - 4 - 2 = - 4KN (constant value)

The constant value means that value of shear force at both the nearest point of section is equal that is

SFE = SFB  = -4KN                                                                                                                      ...(7)

Plot the SFD with the help of above shear force values.

Calculation for bending moment Diagram

Let

The distance of section 1-1 from A is X1

The distance of section 2-2 from A is X2

The distance of section 3-3 from A is X3

The distance of section 4-4 from A is X4

Take left portion of the beam

Take section 1-1, taking moment about section 1-1

BM1-1 = 4.X1

It is the Equation of straight line (Y = mX + C), inclined linear.

Inclined linear means that the value of bending moment at both the nearest point of section is varies with

1982_Example of Shear force and bending moment diagram3.png

It is Equation of the straight line (Y = mX + C), inclined linear.

Inclined linear means that the value of bending moment at both the nearest point of section varies with

2107_Example of Shear force and bending moment diagram4.png

Plot the BMD with the help of obtained bending moment values.

Posted Date: 10/20/2012 1:38:18 AM | Location : United States







Related Discussions:- Example of shear force and bending moment diagram, Assignment Help, Ask Question on Example of shear force and bending moment diagram, Get Answer, Expert's Help, Example of shear force and bending moment diagram Discussions

Write discussion on Example of shear force and bending moment diagram
Your posts are moderated
Related Questions

How can I achieve a back and forth movement of carriage system. How can I reverse the motor to go back and forth.

This is to determine the best possible angle to reduce aerodynamic drag. Mesh is to use tetrahedron of 0.5m wide.  I need the mesh generation and solver control on ansys 11.0. I al

Expression for strain energy: Derive an expression for strain energy because of torsion.                                          Sol.: The work done in straining shaf

Carburettor Tuning :  It is very important that the carburettor is tuned properly to attain the best fuel efficiency and performance of the motorcycle. Since air screw is factory

velocity acceleration by relative method and intentan methodto be showed graphical on it?

State the Planning the foundation for reciprocating engines i)  The eccentricity of  the common centre of gravity of machine and foundation referred to the centroid of base are


To design a cantilevered truss to support the loads shown in the figures, two layouts are proposed as shown in Figs. A and B. All truss members are steel with allowable stress of 2

Working of Drum Type Brake: When we apply brake to the motorcycle that means we are applying force 'F' to the brake shoes. This force pushes the brake shoes towards the drum surf