Example of shear force and bending moment diagram, Mechanical Engineering

Example of Shear force and bending moment diagram:

Q: Draw the Shear Force and bending moment diagram for the simply supported beam loaded as shown in the figure given below. 

 

104_Example of Shear force and bending moment diagram1.png

1080_Example of Shear force and bending moment diagram.png

Sol.: Let reaction at support A and B be, RA  and RB  First find support reaction

For that,

1873_Example of Shear force and bending moment diagram2.png

Taking moment about the point A,

ΣMA = 0

2 X 1 + 4 X 2 + 2 X 3 - RB  X 4 = 0

RB = 4KN                                                                                           ...(2)

From equation (1), RA  = 4KN                                                                                                                       ...(3)

Calculation for Shear force Diagram

Draw the section line, here total four section line, which break the load RA and 2KN(Between A and C),

2KN and 4KN(Between C and D),

4KN and 2KN (Between D and E) and

2KN and RB(Between E and B) Consider left portion of beam Take section 1-1

Force on left of section 1-1 is RA

SF1-1 = 4KN (constant value)

Constant value means value of shear force at both the nearest point of section is equal that is

SFA = SFC  = 4KN                                                                               ...(4)

Take section 2-2

Forces on left of section 2-2 is RA  and 2KN

SF2-2 = 4 - 2 = 2KN (constant value)

Constant value means value of shear force at both the nearest point of section is equal that is

SFC = SFD  = 2KN                                                                                                                        ...(5)

Take section 3-3

Forces on left of section 3-3 is RA, 2KN, 4KN

SF3-3 = 4 - 2 - 4 = -2KN (constant value)

The constant value means that value of shear force at both the nearest point of the section is equal that is

SFD = SFE  = -2KN                                                                                                                      ...(6)

Take section 4-4

Forces on left of the section 4-4 is RA, 2KN, 4KN, 2KN

SF4-4 = 4 - 2 - 4 - 2 = - 4KN (constant value)

The constant value means that value of shear force at both the nearest point of section is equal that is

SFE = SFB  = -4KN                                                                                                                      ...(7)

Plot the SFD with the help of above shear force values.

Calculation for bending moment Diagram

Let

The distance of section 1-1 from A is X1

The distance of section 2-2 from A is X2

The distance of section 3-3 from A is X3

The distance of section 4-4 from A is X4

Take left portion of the beam

Take section 1-1, taking moment about section 1-1

BM1-1 = 4.X1

It is the Equation of straight line (Y = mX + C), inclined linear.

Inclined linear means that the value of bending moment at both the nearest point of section is varies with

1982_Example of Shear force and bending moment diagram3.png

It is Equation of the straight line (Y = mX + C), inclined linear.

Inclined linear means that the value of bending moment at both the nearest point of section varies with

2107_Example of Shear force and bending moment diagram4.png

Plot the BMD with the help of obtained bending moment values.

Posted Date: 10/20/2012 1:38:18 AM | Location : United States







Related Discussions:- Example of shear force and bending moment diagram, Assignment Help, Ask Question on Example of shear force and bending moment diagram, Get Answer, Expert's Help, Example of shear force and bending moment diagram Discussions

Write discussion on Example of shear force and bending moment diagram
Your posts are moderated
Related Questions
The steam that leaves the super-heater is expanded from 130bar at 535°C to 25.2bar at 310°C in a high pressure turbine. The steam from the exit of the HP turbine is reheated to 535

how to calculate the volume of HFO burn to produice steam?

By introducing their model of neural excitability in 1952, Alan Lloyd Hodgkin and Andrew Huxley not only shed light on the mechanism underlying a very important phenomenon in Physi

A special feature of the PDES A special feature of the PDES development is the use of the formal language EXPRESS for modeling the product information. There will be capabiliti

Q. Heavy traffic areas in pumps? These are areas around pumps, filters, control valves, PSV's and other equipment requiring frequent maintenance or servicing. Piping attache

Q. Design Safe Areas for plant? A Safe Area in this manual is regarded as a space that is not ranked as being a designated hazardous area by the relevant Regional or Country st

What are the types of Boundary Layer and what do you understand by separation of Boundary layer. Can you Derive Hagen Poiseulle formula. Aslo illustrate Reynold's No.

4. Design a run-of-the river hydropower scheme for a river in the Scottish Borders with potential level different of 15 m carrying water from a catchment area of 14 km by 25 km. I

Railway operation: Terminal facilities are an important feature of railway operation. These include stations where trains stop and passengers are serviced; and railway yards w

Normal 0 false false false EN-US X-NONE X-NONE