Evaluate power transmitted by belt.
Sol: Let T_{1} = Tension in tight side of the belt
T_{2} = Tension in slack side of the belt
V = Velocity of belt in m/sec.
= Π DN/60 m/sec, D is in meter and N is in RPM P = Maximum power transmitted by belt drive
The effective tension or force acting at circumference of driven pulley is difference between the two tensions (that is T_{1} - T_{2})
Effective driving force = (T_{1}-T_{2})
Work done per second = Force X Velocity = F X V N.m
= (T_{1}-T_{2})X V N.m Power Transmitted = (T_{1}-T_{2}).V/1000 Kw
(Here T_{1 } and T_{2} are in Newton and V is in m/sec)
Note:
1. Torque exerted on driving pulley = (T_{1}-T_{2}).R_{1}
Where R_{1} = radius of driving pulley
2. Torque exerted on driven pulley = (T_{1}-T_{2}).R_{2}
Where R_{2} = radius of driven pulley