Evaluate log function, Algebra

Example   Evaluate log5 7 .

Solution

At first, notice that we can't employ the similar method to do this evaluation which we did in the first set of instance. It would need us to look at the following exponential form,

                                                           5?  = 7

and that's only not something which anyone can answer off the top of their head.  If the 7 had been a 5, or a 25, or a 125, etc. we could do this, however it's not. Thus, we need to use the change of base formula.

Now, we can utilize either one & we'll get the similar answer.  Thus, let's use both & verify that. We'll begin with the common logarithm through of the change of base.

 

log5  7 = log 7/ log 5 = 0.845098040014/0.698970004336 = 1.20906195512

Now, let's attempt the natural logarithm form of the change of base formula.

log5  7 = log 7/ log 5 = 1.94591014906 /0.698970004336 = 1.20906195512

So, we got the same answer despite the fact that the fractions involved different answers.

Posted Date: 4/8/2013 3:24:24 AM | Location : United States







Related Discussions:- Evaluate log function, Assignment Help, Ask Question on Evaluate log function, Get Answer, Expert's Help, Evaluate log function Discussions

Write discussion on Evaluate log function
Your posts are moderated
Related Questions


how do you find the slope to a line that has no given points to it

Question 1 (Multiple Choice Worth 1 points) (05.02) Choose the equivalent system of linear equations that will produce the same solution as the one given below. 4x - 2y = 6 2x +


The following is a double inequality.                                                                   -9 In a double inequality we are saying that both of the inequalities

what is the equation of a line perpendicular to the given line y=-x+3;(-2,-2) but passing through the given point?


#ques1). Using the function: y=y0,(.90)^t-1. In this equation y0 is the amount of initial dose and y is the amount of medication still available t hours after drug is administered.